This way that we have actually 8 wholes and also a fourth. To obtain this in portion form: 1.Take the number in former of the fraction times the denominator

#8*4=32# quarters

2.Now add to the numerator to gain the total variety of quarters

#32+1=33# quarters

So now we have: #(33/4)/3#

We can prolong the 3 come #3/1#

It"s the precisely the exact same thing just various numbers.

Now we have:

#(33/4)/(3/1)#

Now we divide them by flipping the bottom one and also then multiply so we get:

#33/4xx1/3=33/12#

Now we deserve to simplify by dividing by 3 in the numerator and in the denominator so us get

#11/4 = 2 3/4#

Hope this help =).




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Tony B · EZ as pi
Apr 18, 2018

#2 3/4#

A lot of information given therefore you deserve to see the way everything works. In truth you would use a lot much less lines.


Explanation:

Consider the #-:3# this has actually the very same outcome as #xx1/3#So now we have:

#color(blue)(8 1/4xx1/3)#

Consider the #8 1/4#. Compose as #8+1/4#

Multiply through 1 and you execute not change the value. However, 1 comes in plenty of forms

#color(green)( <8 color(red)(xx1)>+1/4 color(white)("dddd")-> color(white)("dddd")<8color(red)(xx4/4)>+1/4#

#color(green)(color(white)("ddddddddddddd")-> color(white)("ddd.dd")<32/4>color(white)("d")+1/4= 33/4 #

#color(green)(8 1/4 = 33/4)#

Putting that all back together we have:

#color(blue)(33/4xx1/3)#

#color(green)((33xx1)/(4xx3)color(white)("dd") =color(white)("dd") (33xx1)/(3xx4)color(white)("dd") =color(white)("dd") cancel(33)^11/cancel(3)^1xx1/4color(white)("d")=color(white)("d")11/4#

#color(blue)(11/4color(white)("dd") ->color(white)("dd")2 3/4 larr" Same format as in the question")#


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EZ as pi
Apr 19, 2018

#11/4 =2 3/4#


Explanation:

To divide v fractions:

Make improper fractions.multiply by the reciprocalcancel whereby possiblemultiply directly across

#8 1/4 div 3#

#= 33/4 xx1/3#

#= cancel33^11/4 xx1/cancel3#

#=11/4#

#= 2 3/4#

Answer in the same style as the question, so provide the answer as a blended number,


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