Acetone (fingernail-polish remover) has a thickness of 0.7857 g/cm3.what is the volume of what is the volume in milliliters that 7.64 g of acetone?

Explanation:

Density is characterized as the mass existing in per unit volume the a substance.

You are watching: Acetone (fingernail-polish remover) has a density of 0.7857 g/cm3.

Mathematically, density =

It is provided that thickness is 0.7857 and also mass is 7.64 g. Therefore, calculation the volume as follows.

density =

0.7857 =

volume = It is known that 1 = 1 ml.

Therefore, we have the right to conclude that volume in ml of given acetone is 9.72 ml.

Answer : The massive of acetone will certainly be, 10.26 grams.

Explanation :

Density : that is characterized as the mass had per unit volume.

Formula offered for density :

Given :

Density that acetone = Volume = 13.06 mL

Now put all the offered values in the above formula, we obtain the massive of acetone.  Therefore, the mass of acetone will certainly be, 10.26 grams.

Mass that acetone = 13.246902 g

Explanation:

Density Mass = thickness × Volume

Volume = 16.86 mL

1 mL = Volume = 16.86 mL = 16.86 cm^3

Mass = density × Volume

= Hope this helps you.

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To understand the massive of the acetone we need to multiply the volume of the acetone with its density. But because the volume is in ml units and also the density is in g/cm3. We must convert it firstsince 1 ml = 1 cm3so mass acetone = 13.06 mL (0.7857 g/ml)mass acetone = 10.848 g

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(b) as soon as heated, heavy calcium chlorate decomposes right into calcium chloride solid, release oxygen gas.