However, ns was previously taught the the maximum number of electrons in the first orbital is 2, 8 in the 2nd orbital, 8 in the third shell, 18 in the fourth orbital, 18 in the fifth orbital, 32 in the 6th orbital. I am reasonably sure the orbitals and also shells space the very same thing.
Which of these two techniques is correct and should be provided to uncover the variety of electrons in an orbital?
I to be in high school so please try to simplify your answer and use relatively basic terms.
You are watching: How many electrons can the 3rd shell hold
physical-ptcouncil.net electron electronic-configuration
boost this question
edited january 22 "17 in ~ 9:54
6,30999 gold badges4242 silver- badges8080 bronze badges
request Feb 20 "14 in ~ 4:13
56733 gold badges77 silver badges1010 bronze badges
add a comment |
3 answer 3
active oldest Votes
Shells and also orbitals space not the same. In terms of quantum numbers, electron in different shells will certainly have different values of principal quantum number n.
To answer her question...
In the an initial shell (n=1), we have:The 1s orbital
In the second shell (n=2), we have:The 2s orbitalThe 2p orbitals
In the 3rd shell (n=3), us have:The 3s orbitalThe 3p orbitalsThe 3d orbitals
In the fourth shell (n=4), us have:The 4s orbitalThe 4p orbitalsThe 4d orbitalsThe 4f orbitals
So another kind the orbitals (s, p, d, f) becomes available as we go come a covering with greater n. The number in prior of the letter signifies which covering the orbital(s) are in. For this reason the 7s orbital will certainly be in the 7th shell.
Now because that the different kinds of orbitalsEach sort of orbital has actually a different "shape", together you deserve to see ~ above the snapshot below. Friend can additionally see that:The s-kind has only one orbitalThe p-kind has actually three orbitalsThe d-kind has 5 orbitalsThe f-kind has seven orbitals
Each orbital can hold two electrons. One spin-up and one spin-down. This method that the 1s, 2s, 3s, 4s, etc., have the right to each host two electrons because they each have actually only one orbital.
The 2p, 3p, 4p, etc., can each host six electrons due to the fact that they each have three orbitals, that can hold two electrons every (3*2=6).
The 3d, 4d etc., deserve to each organize ten electrons, since they each have five orbitals, and each orbital can hold two electron (5*2=10).
Thus, to discover the number of electrons feasible per shell
First, we look in ~ the n=1 covering (the very first shell). That has:The 1s orbital
An s-orbital holds 2 electrons. Therefore n=1 shell have the right to hold two electrons.
The n=2 (second) covering has:The 2s orbitalThe 2p orbitals
s-orbitals have the right to hold 2 electrons, the p-orbitals deserve to hold 6 electrons. Thus, the second shell have the right to have 8 electrons.
The n=3 (third) covering has:The 3s orbitalThe 3p orbitalsThe 3d orbitals
s-orbitals deserve to hold 2 electrons, p-orbitals can hold 6, and also d-orbitals can hold 10, because that a full of 18 electrons.
Therefore, the formula $2n^2$ holds! What is the difference in between your two methods?
There"s an essential distinction in between "the variety of electrons feasible in a shell" and also "the variety of valence electrons feasible for a duration of elements".
See more: All I Ask Of You Raphael Saadiq On Apple Music, Ask Of You Lyrics
There"s space for $18 \texte^-$ in the 3rd shell: $3s + 3p + 3d = 2 + 6 + 10 = 18$, however, elements in the 3rd period only have up to 8 valence electrons. This is due to the fact that the $3d$-orbitals aren"t filled until we acquire to facets from the 4th period - ie. Aspects from the third period don"t to fill the 3rd shell.
The orbitals space filled so the the people of lowest power are to fill first. The energy is around like this: