For this problem, we’re being asked todetermine thenumber the oxygen atoms in 7.00 g of salt dichromate, Na2Cr2O7.

You are watching: How many oxygen atoms are there in 7.00 g of sodium dichromate, na2cr2o7?

Recall thatAvogadro’s Numbergives united state thenumber the entities current in 1 mole:

There are6.022 × 1023O atomsin 1 moleNa2Cr2O7

We will do the adhering to calculations to deal with for # of O atom in 7.00 g sodium dichromate:

mass → moles calculation for Na2Cr2O7 (molar mass)

mole Na2Cr2O7 → moles O

**Based top top the molecular formula, there are7 moles of O because that every 1 mole ofNa2Cr2O7

moles → atomscalculation based onAvogadro"s number

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Problem Details

How countless oxygen atoms room there in 7.00 g of salt dichromate, Na 2Cr2O7?

a. 1.13 x 1023 oxygen atoms

b. 2.30 x 1021 oxygen atoms

c. 1.60 x 1022 oxygen atoms

d. 0.187 oxygen atoms

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Our tutors have indicated the to fix this problem you will require to apply the Mole concept concept. You can view video clip lessons to discover Mole Concept. Or if girlfriend need more Mole ide practice, girlfriend can likewise practice Mole concept practice problems.

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Based on ours data, we think this difficulty is relevant for Professor Bertolini's class at USC.

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