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depending on what you median by "exist", the answer come your concern is correct . There is an N=3 Poincaré supersymmetry algebra, and there room field-theoretic realisations. In particular there is a ...

as Claude Leibovici wrote, your factorization is false. Due to the fact that 3^x is fallout’s slowlier than 5^x we have actually to factor out 3^x and get: frac3^xln^2(3)+5^xln^2(5)3^xln(3)+5^xln(5)=frac3^xleft(ln^2(3)+left(frac53 ight)^xln^2(5) ight)3^xleft(ln(3)+left(frac53 ight)^xln(5) ight)=fracln^2(3)+left(frac53 ight)^xln^2(5)ln(3)+left(frac53 ight)^xln(5) ...

https://math.stackexchange.com/questions/1008446/put-2600-3500-4400-5300-and-6200-in-order-from-leas

together (a^b)^100 = a^100b because that all confident a and b, this difficulty is the exact same as notified 2^6, 3^5, 4^4, 5^3 and 6^2 i beg your pardon is right forward.

Area = int_1^3 left<(x+1) - frac2x ight>dx A = left

See more: For All Intents And Purposes In A Sentence, To All Intents And Purposes

because that the second function, rewrite it as g(x) = -1 + frac21-x Then apply what you recognize for frac11-x, i beg your pardon is the geometric series -1 + 2cdotfrac11-x = -1 + 2sum_n=0^inftyx^n ...

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left< eginarray together l 2 & 3 \ 5 & 4 endarray ight> left< eginarray together l together 2 & 0 & 3 \ -1 & 1 & 5 endarray ight>

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