### p1v1/t1=p2v2/t2

This encounters adding, subtracting and finding the least common multiple.

You are watching: P1v1 t1 p2v2 t2 solve for v2

## Step by action Solution

### Reformatting the input :

Changes made to your input must not affect the solution: (1): "t2" was replaced by "t^2". 5 much more similar replacement(s).### Rearrange:

Rearrange the equation by individually what is to the appropriate of the equal sign from both political parties of the equation : p^1*v^1/t^1-(p^2*v^2/t^2)=0## Step by action solution :

## Step 1 :

v2 leveling —— t2Equation in ~ the end of action 1 : (v1) v2 ((p1)•————)-((p2)•——) = 0 (t1) t2

## step 2 :

v leveling — tEquation in ~ the finish of action 2 : v p2v2 ((p1) • —) - ———— = 0 t t2## Step 3 :

Calculating the Least usual Multiple :3.1 discover the Least common Multiple The left denominator is : t The ideal denominator is : t2Number the times each Algebraic Factorappears in the administrate of:AlgebraicFactorLeftDenominatorRightDenominatorL.C.M = MaxLeft,Rightt | 1 | 2 | 2 |

Least typical Multiple: t2

Calculating multiplier :3.2 calculate multipliers because that the two fractions signify the Least common Multiple by L.C.M signify the Left Multiplier by Left_M represent the right Multiplier by Right_M denote the Left Deniminator by L_Deno represent the right Multiplier by R_DenoLeft_M=L.C.M/L_Deno=tRight_M=L.C.M/R_Deno=1

Making equivalent Fractions :3.3 Rewrite the 2 fractions into indistinguishable fractionsTwo fractions are referred to as equivalent if they have the same numeric value. For example : 1/2 and also 2/4 room equivalent, y/(y+1)2 and also (y2+y)/(y+1)3 are indistinguishable as well. To calculate equivalent portion , multiply the numerator of every fraction, by its particular Multiplier.

L. Mult. • L. Num. Pv • t —————————————————— = —————— L.C.M t2 R. Mult. • R. Num. P2v2 —————————————————— = ———— L.C.M t2 adding fractions that have actually a usual denominator :3.4 including up the two identical fractions include the two identical fractions which now have a typical denominatorCombine the molecule together, placed the sum or distinction over the usual denominator then minimize to lowest terms if possible:

pv • t - (p2v2) pvt - p2v2 ——————————————— = —————————— t2 t2

## Step 4 :

Pulling out favor terms :4.1 pull out favor factors:pvt - p2v2=-pv•(pv - t)Equation in ~ the finish of step 4 : -pv • (pv - t) —————————————— = 0 t2

## Step 5 :

When a fraction equals zero :5.1 once a fraction equals zero ...Where a portion equals zero, its numerator, the part which is above the fraction line, must equal zero.Now,to eliminate the denominator, Tiger multiplys both political parties of the equation by the denominator.Here"s how:-pv•(pv-t) —————————— • t2 = 0 • t2 t2 Now, top top the left hand side, the t2 cancels the end the denominator, while, ~ above the best hand side, zero time anything is tho zero.The equation now takes the shape:-pv • (pv-t)=0

Theory - root of a product :5.2 A product of number of terms equates to zero.When a product of 2 or more terms equals zero, then at least one of the terms should be zero.We shall now solve each term = 0 separatelyIn other words, we space going to deal with as plenty of equations as there space terms in the productAny equipment of ax = 0 solves product = 0 together well.

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Solving a single Variable Equation:5.3Solve-pv=0 setting any the the variables to zero solves the equation:p=0v=0

Solving a solitary Variable Equation:5.4Solvepv-t=0 In this type of equations, having much more than one variable (unknown), you have to specify because that which change you desire the equation solved.We shall not handle this form of equations in ~ this time.