Here friend go.By the way, once you word her questions, if the number on your worksheet looks prefer this: 
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Then you compose it like this: 7^2 

x^2 − 5x − 2 = 0.

You are watching: What are the exact solutions of x2 = 5x + 2?

a = 1

b = -5

c = -2

x = (5 +- sqrt(25 +8)) / 2

x1 = 5.3723

x2 = -0.37228

Step-by-step explanation:





A quadratic equation

*
,....<1> then the systems of this is provided by:

*
....<2>

Given the quadratic equation:

*

We deserve to write this as:

*

On comparing v <1> we have;

a = 1, b = -5 and also c = -2

Substitute this in <2> we have

*

⇒

*

Simplify:

*

Therefore, the specific solutions the the offered equations are:

*
and
*



a. X equals 5 add to or minus the square root of 33, everywhere 2

Step-by-step explanation:

x = (5 +- √25+8)/2 = (5 +- √33)/2

sounds choose x amounts to 5 plus or minus the square source of 33, almost everywhere 2 come me


A. X amounts to 5 add to or minus the square root of thirty-three everywhere 2

Step-by-step explanation:

Let"s relocate all the terms to one side:

*

*

Now, we desire to usage the quadratic formula, which states that for a quadratic equation that the type

*
, the roots can be uncovered with the equation:
*
or
*
.

Here, a = 1, b = -5, and c = -2, for this reason plug these in:

*

OR

*

Thus, the prize is A.

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Hope this helps!


First one:

x = x equates to 5 add to or minus the square source of thirty-three everywhere 2

Step-by-step explanation:

x² = 5x + 2

x² - 5x - 2 = 0

Using quadratic formula:

x = <-(-5) +/- sqrt<(-5)² - 4(1)(-2)>/2(1)

x = <5 +/- sqrt(33)>/2


Part 1) x=3

Part 2) x = −1.11 and x = 1.11

Part 3) 105

Part 4) a = −6, b = 9, c = −7

Part 5) x equals 5 plus or minus the square root of 33, all over 2

Part 6) In the procedure

Part 7)

Part 8) The denominator is 2

Part 9) a = −6, b = −8, c = 12

Step-by-step explanation:

we recognize that

The formula to solve a quadratic equation the the form is same to

Part 1)

in this difficulty we have

*

so

*

substitute in the formula

*

*

*

Part 2) in this problem we have

*

so

*

substitute in the formula

*

*

*

Part 3) as soon as the systems of x2 − 9x − 6 is expressed as 9 add to or minus the square root of r, almost everywhere 2, what is the value of r?

in this difficulty we have

*

so

*

substitute in the formula

*

*

therefore

*

Part 4) What room the worths a, b, and c in the following quadratic equation?

−6x2 = −9x + 7

in this trouble we have

*

*

so

*

Part 5) use the quadratic formula to discover the precise solutions the x2 − 5x − 2 = 0.

In this problem we have

*

so

*

substitute in the formula

*

*

therefore

x equates to 5 to add or minus the square source of 33, everywhere 2

Part 6) Quadratic Formula proof

we have

Divide both political parties by a

*

Complete the square

*

*

Rewrite the perfect square trinomial ~ above the left next of the equation together a binomial squared