x^2 − 5x − 2 = 0.

You are watching: What are the exact solutions of x2 = 5x + 2?

a = 1

b = -5

c = -2

x = (5 +- sqrt(25 +8)) / 2

x1 = 5.3723

x2 = -0.37228

Step-by-step explanation:

A quadratic equation

,....<1> then the systems of this is provided by: ....<2>Given the quadratic equation:

We deserve to write this as:

On comparing v <1> we have;

a = 1, b = -5 and also c = -2

Substitute this in <2> we have

⇒

Simplify:

Therefore, the specific solutions the the offered equations are:

anda. X equals 5 add to or minus the square root of 33, everywhere 2

Step-by-step explanation:

x = (5 +- √25+8)/2 = (5 +- √33)/2

sounds choose x amounts to 5 plus or minus the square source of 33, almost everywhere 2 come me

A. X amounts to 5 add to or minus the square root of thirty-three everywhere 2

Step-by-step explanation:

Let"s relocate all the terms to one side:

Now, we desire to usage the quadratic formula, which states that for a quadratic equation that the type

, the roots can be uncovered with the equation: or .Here, a = 1, b = -5, and c = -2, for this reason plug these in:

OR

Thus, the prize is A.

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Hope this helps!

First one:

x = x equates to 5 add to or minus the square source of thirty-three everywhere 2

Step-by-step explanation:

x² = 5x + 2

x² - 5x - 2 = 0

Using quadratic formula:

x = <-(-5) +/- sqrt<(-5)² - 4(1)(-2)>/2(1)

x = <5 +/- sqrt(33)>/2

Part 1) x=3

Part 2) x = −1.11 and x = 1.11

Part 3) 105

Part 4) a = −6, b = 9, c = −7

Part 5) x equals 5 plus or minus the square root of 33, all over 2

Part 6) In the procedure

Part 7)

Part 8) The denominator is 2

Part 9) a = −6, b = −8, c = 12

Step-by-step explanation:

we recognize that

The formula to solve a quadratic equation the the form is same to

Part 1)

in this difficulty we have

so

substitute in the formula

Part 2) in this problem we have

so

substitute in the formula

Part 3) as soon as the systems of x2 − 9x − 6 is expressed as 9 add to or minus the square root of r, almost everywhere 2, what is the value of r?

in this difficulty we have

so

substitute in the formula

therefore

Part 4) What room the worths a, b, and c in the following quadratic equation?

−6x2 = −9x + 7

in this trouble we have

so

Part 5) use the quadratic formula to discover the precise solutions the x2 − 5x − 2 = 0.

In this problem we have

so

substitute in the formula

therefore

x equates to 5 to add or minus the square source of 33, everywhere 2

Part 6) Quadratic Formula proof

we have

Divide both political parties by a

Complete the square

Rewrite the perfect square trinomial ~ above the left next of the equation together a binomial squared