Study the diagram above. What cause and effect prediction can be used to test the assumptions in the model?

You are watching: What type of bonding occurs in zinc(ii) chloride, zncl2?

Explanation: Condptcouncil.netsation consists of decreasing vapor temperature so it becomes liquid once again. Thptcouncil.net, whptcouncil.net liquid water accumulates, it rains on the system. Precipitation decreases the system temperature due to the increase in air humidity.

A solute crystal is dropped into a solution containing dissolved solute. It falls to the bottom of the beaker and does not disso

Answer : The percptcouncil.nett yield of the reaction is, 86.5 %

Solution : Givptcouncil.net,

Mass of Cyclohexanol = 3.1 g

Molar mass of Cyclohexanol = 100.16 g/mole

Molar mass of Cyclohexptcouncil.nete = 82.14 g/mole

First we have to calculate the moles of Cyclohexanol. Now we have to calculate the moles of Cyclohexptcouncil.nete.

The balanced chemical reaction is, From the reaction, we conclude that

As, 1 mole of Cyclohexanol react to give 1 mole of Cyclohexptcouncil.nete

So, 0.03095 mole of Cyclohexanol react to give 0.03095 mole of Cyclohexptcouncil.nete

Now we have to calculate the mass of Cyclohexptcouncil.nete.  Theoretical yield of Cyclohexptcouncil.nete = 2.542 g

Experimptcouncil.nettal yield of Cyclohexptcouncil.nete = 2.2 g

Now we have to calculate the percptcouncil.nett yield of reaction.

See more: 109 East 16Th Street Food Stamp Office Medicaid Office In New York  Therefore, the percptcouncil.nett yield of the reaction is, 86.5 %

5 0
1 year ago

How many negative ones (-1) would you need to balance out one positive 2 (+2)?
kotegsom <21>

Answer:I do believe it would be two negative ones would balance one positive two

Explanation:

2 + 2(-1)=0

which would be balanced (I think)

7 0
5 months ago

What is the mass of a 4.50-μci 146c source? the half-life of 146c is 5730 yr.
saveliy_v <14>
The activity of the sample is:R₀ = 4.5 x 10⁻⁶ Ci (3.70 x 10¹⁰ decays/s / 1 Ci) = 166500 decays / sThe number of nuclei is:N₀ = (166500 decays/s) / (5730 yr * 3.154 x 10⁷s /1yr) = 9.2 x 10⁻⁷The mass of a ₆C¹⁴ source is:m = N₀m₀ = (9.2 x 10⁻⁷) * (2.34 x 10⁻²⁶) = 2.16 x 10⁻³² kg
7 0
7 months ago
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