Because lithium is losing an electron, it will certainly consequently have actually one much more proton than electron, make it confident (rule out 1 and also 2). A cation is always smaller 보다 its neutral atom, for this reason 3 is her ptcouncil.net.

You are watching: When an atom of lithium loses an electron the atom becomes a



ptcouncil.net: when a lithium atom looses an electron, the atom i do not care a confident ion v a radius smaller than the radius that the atom

Explanation:

Lithium is the third element of the routine table having electronic configuration the

*
.

This element will loose 1 electron to kind

*
(positive) ion.

There are two types of ions:

Cations: lock are developed when an atom looses its valence electrons. Lock are hopeful ions.Anions: castle are developed when an atom gain electron in that is outermost shell. Castle are negative ions.

For positive ions, the removal of electron boosts the nuclear fee for an outermost electron because the outermost electron are much more strongly attracted by the cell core that have actually same variety of protons. So, the reliable nuclear charge boosts for cations. This outcomes in the shrinkage that atom and also thus decrease in the radius of atom is observed.

See more: How Do You Say Good Morning In Tagalog ? Most Common Tagalog Greetings

Hence, as soon as a lithium atom looses one electron, the atom becomes a positive ion v a radius smaller sized than the radius the the atom


Send
You might be interested in

What is the minimum frequency that light forced to observe the photoelectric result on pd
Tems11 <23>

ptcouncil.net:

1.26 × 10¹⁵ s⁻¹

Explanation:

Work role is the minimum energy required to remove an electron from the surface of metal

energy that the electron = hf - Φ

Φ = work duty = hf₀ where f₀ = threshold frequency

f₀ = Φ / h whereby h ( Planck continuous = 6.626 × 10⁻³⁴ Js)

Φ = 5.22eV = 5.22 × 1 eV where 1 eV = 1.60217662 × 10⁻¹⁹ J

Φ = 5.22 × 1.60217662 × 10⁻19 J = 8.363362 × 10⁻¹⁹ J

f₀ = (8.363362 ×10⁻¹⁹ J) / (6.626× 10⁻³⁴ Js) = 1.26 × 10¹⁵ s⁻¹

The frequency must be greater than the 1.26 × 10¹⁵ s⁻¹ to observe the emission


3 0
1 year ago

what element is this atom? need the ptcouncil.net in 30 minutes. Feel free to ptcouncil.net the other questions. Require HELP!
alexandr402 <8>

ptcouncil.net:

fluorine

Explanation:

I offered the variety of electrons to identify it.


4 0
10 months ago
Read 2 more ptcouncil.nets

Write 5,600 in clinical notation
MA_775_DIABLO <31>
5.6 x 10^3 expect this helps!
7 0
2 months ago
Read 2 more ptcouncil.nets

Consider the adhering to reaction: COCl2(g) ⇌ CO(g) + Cl2(g) A reaction mixture initially consists of 1.6 M COCl2. Recognize the equi
professor190 <17>

ptcouncil.net:

The equilibrium concentration that CO is 0.0361 M

Explanation:

Step 1: Data given

Kc = 8.33 *10^-4

Molarity that COCl2 = 1.6 M

Step 2: The well balanced equation:

COCl2(g) ⇌ CO(g) + Cl2(g)

Step 3: Calculate last concentrations

The early concentration that COCl2 = 1.6M

The initial concentration that CO and also Cl2 = 0M

There will certainly react xM the COCl2

Since the mole ratio is 1:1

The final concentration the CO and Cl2 will certainly be X M

The last concentration the COCl2 will certainly be (1.6 -X)M

Step 4: define Kc

Kc= * / = 8.33*10^-4

Kc = X*X / 1.6-X = 8.33 * 10^-4

8.33 * 10^-4 = X² /(1.6-X)

8.33 * 10^-4 *(1.6 -X) = X²

0.0013328 - 8.33*10^-4 X = X²

X² + 8.33*10^-4 X - 0.0013328= 0

X = 0.0361 M = =

= 1.6 - 0.0361 = 1.5639 M

To control this we have the right to calculate the Kc

(0.0361*0.0361)/1.5639 = 0.000833


5 0
10 months ago
For your an initial experiment in your middle school class, you desire to know which variety of tomato will grow the many tomatoes. You
Semmy <17>

ptcouncil.net:

if you plant them every at the very same time they should all prosper evenly..or somehow evenly

Explanation:

I"m thinking but if they room all different I think the doesnt issue bc they space all the very same plant..ptcouncil.net know?


8 0
7 months ago
Other questions:
×
Add ptcouncil.net
Send
×
Login
E-mail
Password
remember me
Login
not registered? fast signup
×
Signup
Your nickname
E-mail
Password
Signup
near
Login Signup
ask question!