this expression stand for a real number once the imaginer part =0

(6+3i)(x+yi) = 6x+6yi+3ix+3yi² i²=-1

(6+3i)(x+yi) = 6x+6yi+3ix-3y

(6+3i)(x+yi) = 6x-3y +(6y+3x)istandard form

the imaginer component is : 6y+3x=0

for x=6 and y= - 3 : 6(-3)+3(6) =0

Lena reflected this figure throughout the x-axis. She writes the vertices that the image as a"(−2, 8), b"(−5, 6), c"(−8, 8), d"(−4, 2).

You are watching: Which values of x and y would make the following expression represent a real number?

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Which values of x and y would make the following expression stand for a actual number?(6 + 3/)(x + y...

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